08-27-2016, 09:49 AM
It's right, but could be done without the line stuff.
distance = time * velocity
Car A: x = t * 51
Car B: x - 1 = t * 50
(Car B travels 1 mile less in the same amount of time)
Two variables, two equations. You can do a number of solving methods, but I'll just substitute.
(t*51) - 1 = t*50
t-1 = 0
t = 1
Time is 1 hour.
To find the distance, use t in either of the above equations.
x = t * 51
x = 1 * 51
x = 51
51 Miles.
distance = time * velocity
Car A: x = t * 51
Car B: x - 1 = t * 50
(Car B travels 1 mile less in the same amount of time)
Two variables, two equations. You can do a number of solving methods, but I'll just substitute.
(t*51) - 1 = t*50
t-1 = 0
t = 1
Time is 1 hour.
To find the distance, use t in either of the above equations.
x = t * 51
x = 1 * 51
x = 51
51 Miles.
In Progress: MBA - HAUniv, Anticipated 2024
Completed: BSBA OpMgmt - TESU June 2021
UG - AP Tests: 20 credits | APICS: 12 Credits | CLEP: 6 credits | Saylor Academy: 6 credits | Sophia.org: 27 credits | Study.com: 12 credits | Davar Academy: 3 credits | TESU: 15 credits | Other College: 99.5 credits
GR - HAUniv: 9 credits
Completed: BSBA OpMgmt - TESU June 2021
UG - AP Tests: 20 credits | APICS: 12 Credits | CLEP: 6 credits | Saylor Academy: 6 credits | Sophia.org: 27 credits | Study.com: 12 credits | Davar Academy: 3 credits | TESU: 15 credits | Other College: 99.5 credits
GR - HAUniv: 9 credits