06252019, 05:20 PM
this is the full problem.
Math Help

06252019, 05:23 PM
(This post was last modified: 06252019, 05:27 PM by MrBossmanJr.)
Would you need to multiply the top and bottom by (cos+1)? Hmm...
Edit: Nevermind. I don't know anything anymore lol.
Boston University: MS in Software Development (20/32 SH  1 Course IP)  GPA: 3.88
Thomas Edison State University: BA in Liberal Studies  GPA: 4.00  AS in Natural Science and Mathematics (Computer Science, Mathematics)  Certificate in Electronics Excelsior College: AAS in Technical Studies (Electronic/Instrumentation Technologies)  High Honors GPA: 3.79 Community College: AAS in Applied Science and Engineering Technology  Highest Honors GPA: 3.91  AAS in Technical Studies (Computer Technology) Epsilon Pi Tau International Honor Society  Golden Key International Honor Society  Phi Theta Kappa Honor Society
06252019, 05:29 PM
(This post was last modified: 06252019, 05:45 PM by Giantzebra.)
I tried that .... I'm not sure .... Maybe there are some trig properties that I'm missing ...
I think you need to graph it but I'm not sure how.
06252019, 05:50 PM
(This post was last modified: 06252019, 05:57 PM by MrBossmanJr.)
Is the answer 1/2?
I think you have to use L'Hospitals Rule. f(0) = (cosx1)/(xsinx) so the denominator is basically 0*0 or x*x at this point which is x^2 cosx1 can be written as 1+cosx or (1cosx) Then you apply the rule and do the derivative of top and bottom the top becomes sinx and the bottom is 2x the x's cancel and become 1's therefore being 1/2?
Boston University: MS in Software Development (20/32 SH  1 Course IP)  GPA: 3.88
Thomas Edison State University: BA in Liberal Studies  GPA: 4.00  AS in Natural Science and Mathematics (Computer Science, Mathematics)  Certificate in Electronics Excelsior College: AAS in Technical Studies (Electronic/Instrumentation Technologies)  High Honors GPA: 3.79 Community College: AAS in Applied Science and Engineering Technology  Highest Honors GPA: 3.91  AAS in Technical Studies (Computer Technology) Epsilon Pi Tau International Honor Society  Golden Key International Honor Society  Phi Theta Kappa Honor Society
06252019, 06:13 PM
(06252019, 05:50 PM)MrBossmanJr Wrote: Is the answer 1/2? Ya  that seems like it makes sense. Thanks!
07092019, 11:59 AM
Objects moving in two dimensions can be hard to track, unless you use calculus to handle the motion. If an object is moving so its X coordinate follows the equation X = 2t + 1 and its Y coordinate follows the equation Y = t2 + 2, where t is the time in seconds, what is the object’s twodimensional speed at t = 2 seconds?
How do you solve this problem?
07092019, 12:59 PM
(This post was last modified: 07092019, 01:04 PM by MrBossmanJr.)
(07092019, 11:59 AM)Giantzebra Wrote: Objects moving in two dimensions can be hard to track, unless you use calculus to handle the motion. If an object is moving so its X coordinate follows the equation X = 2t + 1 and its Y coordinate follows the equation Y = t2 + 2, where t is the time in seconds, what is the object’s twodimensional speed at t = 2 seconds? Don't you just differentiate both the equations? So x = t and y = 2t. Plug in t = 2 and you get (2,4). It's asking for speed so you do differentiate. Speed (not a vector) is just the positive value of velocity (vector). The first equation should provide distance. Differentiating it once will provide velocity and another time will output acceleration.
Boston University: MS in Software Development (20/32 SH  1 Course IP)  GPA: 3.88
Thomas Edison State University: BA in Liberal Studies  GPA: 4.00  AS in Natural Science and Mathematics (Computer Science, Mathematics)  Certificate in Electronics Excelsior College: AAS in Technical Studies (Electronic/Instrumentation Technologies)  High Honors GPA: 3.79 Community College: AAS in Applied Science and Engineering Technology  Highest Honors GPA: 3.91  AAS in Technical Studies (Computer Technology) Epsilon Pi Tau International Honor Society  Golden Key International Honor Society  Phi Theta Kappa Honor Society
07092019, 01:20 PM
(07092019, 12:59 PM)MrBossmanJr Wrote:But the correct answer to the question was √20 feet per second(07092019, 11:59 AM)Giantzebra Wrote: Objects moving in two dimensions can be hard to track, unless you use calculus to handle the motion. If an object is moving so its X coordinate follows the equation X = 2t + 1 and its Y coordinate follows the equation Y = t2 + 2, where t is the time in seconds, what is the object’s twodimensional speed at t = 2 seconds?
07092019, 01:24 PM
(This post was last modified: 07092019, 01:25 PM by MrBossmanJr.)
Ahhh, my bad forgot to mention. I found you the x and y values, but you need to do the pyrgahteka theorem to find the answer. 2^2 + 4^2 and square root the answer. Therefore, you come out with sq rt 20.
EDIT: My spelling is terrible and I can't remember the guy's name lol.
Boston University: MS in Software Development (20/32 SH  1 Course IP)  GPA: 3.88
Thomas Edison State University: BA in Liberal Studies  GPA: 4.00  AS in Natural Science and Mathematics (Computer Science, Mathematics)  Certificate in Electronics Excelsior College: AAS in Technical Studies (Electronic/Instrumentation Technologies)  High Honors GPA: 3.79 Community College: AAS in Applied Science and Engineering Technology  Highest Honors GPA: 3.91  AAS in Technical Studies (Computer Technology) Epsilon Pi Tau International Honor Society  Golden Key International Honor Society  Phi Theta Kappa Honor Society
07092019, 01:29 PM
(This post was last modified: 07092019, 01:36 PM by Giantzebra.)
(07092019, 01:24 PM)MrBossmanJr Wrote: Ahhh, my bad forgot to mention. I found you the x and y values, but you need to do the pyrgahteka theorem to find the answer. 2^2 + 4^2 and square root the answer. Therefore, you come out with sq rt 20. Thanks. Do you also know how the extreme value theorem can be true if f(x) = x is continuous on every closed interval but has no minimum or maximum? (07092019, 01:29 PM)Giantzebra Wrote:(07092019, 01:24 PM)MrBossmanJr Wrote: Ahhh, my bad forgot to mention. I found you the x and y values, but you need to do the pyrgahteka theorem to find the answer. 2^2 + 4^2 and square root the answer. Therefore, you come out with sq rt 20. And, why do the Pythagorean theorem? 
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